Critical item 2:
1.
Calculate the number of moles of methane (CH4) there are
in 25.0 g of methane.
answer
2.
Calculate the number of grams of ethane (C2H6)
there are in 15.0 mole of ethane.
answer
M = m / n
M(CH4) = 16.0 g mol-1
16.0 g mol-1 = 25.0 g / n
n = 1.56 mol
M = m / n
M(C2H6) = 30.0 g mol-1
30.0 g mol-1 = m / 15.0 mol
m = 450 g