How to determine the approximate van't Hoff factor
Summary
In the following discussion, the solvent is water.  The general principles apply to all solvent, but the details vary.

Some relevant definitions:

Electrolyte:  This is a compound which forms hydrated ions in solution.  It resultant solution has the property that it conducts electricity to some extent.

Non electrolyte:  This is a compound which does not form hydrated ions in solution.  It resultant solution has the property that it conducts electricity about as poorly as pure water..

Strong electrolyte:  This electrolyte completely (>98%) dissociates into the hydrated ions in solution.  It resultant solution has the property that it conducts electricity very well.

Weak electrolyte:  This electrolyte dissociates into the hydrated ions in solution to only a limited extent.  It resultant solution has the property that it conducts electricity poorly, but better than pure water.

What is the van't Hoff factor:footnote1

The van't Hoff factor, symbol i,  expresses how may ions and particles are formed (on an average) in a solution from one formula unit of solute.

    Examples:

How to determine the approximate van't Hoff factor:

The first step is to be able to recognize whether one is dealing with an electrolyte or a non electrolyte.  It is easier to recognize electrolytes, although the student by this point should be able to recognize the following organic functional groups which are associated with non electrolytes (not a complete list).  The dashes, - and >, correspond to covalent bonds to another atom, usually C.

If you are not familiar with these groups, go back to some of the CHE 121 handouts.

To recognize electrolytes:

All acids, bases and salts are electrolytes.  The definitions of these terms are found in CHE 121 handouts.  This includes the salts and acids of the polyions.  Thus, you need to know your polyion list which is in your lab manual or in the CHE 121 handouts.  You must also know this list in order!  Below is the some of the list in the form of the acids.  Notice the lines which delineate the 8 acids in the upper right.
 

HClO
HClO2
HClO3
HClO4
HBrO
HBrO2
HBrO3
HBrO4
HIO
HIO2
HIO3
HIO4
 
H2SO3
H2SO4
 
 
HNO2
HNO3
 
   
H3PO2
H3PO3
 
H3PO4
 
     
H2CO3
 

Strong acids: (belong to the class of strong electrolytes)

The strong acids completely break up into hydronium ions and the anions in solution.  The following are the strong acids:

The binary acids HCl, HBr and HI  (the hydrohalic acids except for HF).  Thus, for example, HCl dissolves in water by the reaction:

                HCl (g)  +  H2O   -->   H3O+   +   Cl-

This gives a van't Hoff factor or 2.   (i = 2)

The 8 ternary acids in the upper right side of the table above (to the right and above the blank non-tabled boxes presented) are all strongfootnote3.  Thus, for example, HClO4 dissolves in water by the reaction:

                HClO4   +  H2O   -->   H3O+   +   ClO4-

This gives a van't Hoff factor or 2.   (i = 2)

All other acids are weak, including the organic acids which have the functional group -COOH.

Weak Acids:   (belong to the class of weak electrolytes)

All weak acids have a van't Hoff factor of approximately 1.

Example:  The acid HClO2 has a van't Hoff factor of 1.  This acid is, according to the table above, a weak acid.

Example:  The acid HF has a van't Hoff factor of 1.  This binary acid is not HCl, HBr or HI and is therefore a weak acid.

Example:  The acid CH3COOH has a van't Hoff factor of 1.  This acid is not a mineral acid, but rather an organic acid.  All organic acids, if they dissolve, are weak acids in water solutions.

Strong Soluble Bases:

The strong soluble bases are the hydroxide compounds of group I metals and group II metals from Ca down on the periodic chart.  All other metal hydroxides are insoluble bases and only a very small amount will dissolve in water.  (Notice that OH- was on your polyion list!)

Examples:

LiOH has a van't Hoff factor of two.   LiOH is a strong soluble base (group 1 metal hydroxide) and dissolves in water according to:

    LiOH (s)  -->  Li+  +  OH-

Thus, each formula unit yields two ions total.

Ca(OH)2 has a van't Hoff factor of three.   Ca(OH)2 is a strong soluble base (group 1 metal hydroxide) and dissolves in water according to:

    Ca(OH)2 (s)  -->  Ca2+  +  2OH-

Thus, each formula unit yields three ions total.

Insoluble Bases:

These are irrelevant since they are insoluble in water.  Examples include:  Mg(OH)2,  Fe(OH)3,
Zn(OH)2, etc.

Weak Soluble Bases:

Most weak soluble bases may be recognized by being nitrogen compounds.  These are either amines (see above) or are nitrogen compounds with nitrogen covalently bonded to hydrogen.

Examples:

    ammonia  NH3
    methyl amine  CH3NH2
    hydrazine  H2NNH2
 

 Salts are Strong Electrolytes:footnote4

 Salt break up into their ions.  For binary salts break into the individual metal ions (cations) and nonmetal ions (anions)
Some typical examples:
NaCl(s)  -->  Na+  +  Cl  i = 2
Li2S(s)  -->  2Li+  +  S2- i = 3
CaBr2(s)  -->  Ca2+  +  2Br- i = 3
FeCl3(s)  -->  Fe3+  +  3Cl- i = 4

For salts with polyions (here's where you need to know your polyions - learn them if you haven't by now) break up into metal ion (cation) and the polyion as a unit.
Some typical examples
Na2SO42- (s)  -->  2Na+  +  SO42- i = 3 
Fe3(PO4)2 (s)  -->  3Fe2+  +  2 PO43- i = 5

Summary:

All water soluble compounds have a van't Hoff factor of approximately 1 except:

    Compounds which begin with a metal ions.  These include salts and strong bases
    Strong acids - so you need to be able to recognize a strong acid.
    Strong soluble bases - so you need to be able to recognize a strong soluble base.     Back to top



footnote 1:  This discussion is for the determination of the van't Hoff factor in very dilute solutions.  The effect of the associated ionic species will be ignored in this discussion.  The student should be cautioned that in concentrated solutions the van't Hoff factor will be somewhat less than that figured by this discussion.  This is due to some association of the ions with each other in solutions to form dimer (two particle) and large species.  Such corrections to the van't Hoff factor may be typically be found in handbooks.  At 0.01 M or less this association effect is a very small correction.     BACK

footnote 2:  Both weak acids and weak bases dissociate to a small extent, but not enough to change the conclusion about the approximate van't Hoff factor.  This dissociation will become a topic of considerable study in the next few sections of CHE 122 BACK

footnote 3:  H2SO4 is a strong acid for only the removal of the first proton.  HSO4- is a weak acid.  This complication will be avoided for the present, but will be revisited with the lead acid battery.    BACK

footnote 4:  Ok, Ok!  I know there are some very rare exceptions, after all I've worked with water glass.  We will avoid the exceptions.  If the student runs into some in the future, let the amazement flow.     BACK